AdvancedA-002-002-010
If a Zener diode rated at 10 V and 50 watts was operated at maximum dissipation rating, it would conduct ____ amperes:
A
Answer
Circuit design and power supplies
Type
A
5
B
0.5
C
0.05
D
50
Answer Notes
To find the current, you need to use Watt's Law, which states that Power (P) equals Current (I) multiplied by Voltage (E).
By rearranging the formula to solve for current, we get I = P / E. Plugging in the values given in the question, we divide the maximum power dissipation (50 watts) by the Zener voltage (10 V).
50 divided by 10 equals 5 amperes. Therefore, the Zener diode conducts 5 amps when operating at its maximum dissipation rating.
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A Zener diode is a device used to:
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The power-handling capability of most Zener diodes is rated at 25 degrees C or approximately room temperature. If the temperature is increased, the power handling capability is: