AdvancedA-004-004-001
In a series-regulated power supply, the power dissipation of the pass transistor is:
C
Answer
Measurements and troubleshooting
Type
A
dependent upon the peak inverse voltage appearing across the Zener diode
B
indirectly proportional to the load voltage and the input/output voltage differential
C
directly proportional to the load current and the input/output voltage differential
D
the inverse of the load current and the input/output voltage differential
Answer Notes
To understand power dissipation in a series-regulated power supply, you can use the standard power formula: Power (P) = Voltage (V) multiplied by Current (I). In this circuit, the voltage dropped across the pass transistor is the difference between the unregulated input voltage and the regulated output voltage (the input/output voltage differential).
The current flowing through the pass transistor is essentially the load current. Therefore, the power dissipated as heat by the transistor is P = (Vin - Vout) x I_load. This means the power dissipation is directly proportional to both the load current and the voltage differential across the transistor.
Distractors suggesting an 'inverse' or 'indirect' relationship are mathematically incorrect, as increasing either the load current or the voltage drop will increase the heat generated by the component.
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A modern type of regulator, which features a reference, high-gain amplifier, temperature-compensated voltage sensing resistors and transistors as well as a pass element is commonly referred to as a:
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In any regulated power supply, the output is cleanest and the regulation is best: