Assuming a velocity factor of 0.66 what would be the physical length of a typical coaxial stub that is electrically one quarter wavelength long at 14.1 MHz?

To find the physical length of the stub, first calculate the free-space wavelength. Using the formula wavelength = 300 / frequency (in MHz), we get 300 / 14.1, which is approximately 21.27 metres. Next, divide this by 4 to find the quarter-wavelength in free space, which yields 5.319 metres. Finally, multiply this electrical length by the velocity factor (0.66) to account for the slower speed of the RF signal inside the coax. This gives a physical length of 3.51 metres (or about 11.5 feet).