What impedance does a 1/4-wavelength transmission line present to an RF generator when the line is shorted at the far end?

A quarter-wavelength transmission line acts as an impedance inverter. This means it transforms the impedance at its far end to the exact opposite extreme at the generator end. Because the far end is shorted (which represents an impedance of virtually zero ohms), the quarter-wave line transforms this zero impedance into a very high impedance (acting like an open circuit) at the generator. Distractors suggesting it matches the characteristic or generator impedance are incorrect because the termination strictly dictates the presented impedance, completely independently of the line's own characteristic impedance in this extreme inversion case.