GeneralG8B06
What is the total bandwidth of an FM phone transmission having 5 kHz deviation and 3 kHz modulating frequency?
D
Answer
Signals and emissions
Type
A
3 kHz
B
5 kHz
C
8 kHz
D
16 kHz
Answer Notes
To find the total bandwidth of an FM (Frequency Modulation) signal, you must use Carson's Rule. The formula is: Bandwidth = 2 × (peak frequency deviation + highest modulating frequency).
In this question, the peak deviation is given as 5 kHz, and the modulating frequency is 3 kHz. First, add the two values together: 5 kHz + 3 kHz = 8 kHz.
Next, multiply that sum by 2 to account for both sides of the carrier wave. 8 kHz × 2 = 16 kHz total bandwidth. Distractors like 8 kHz are the result of forgetting the multiplier, while 3 kHz and 5 kHz are just the raw variables.
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Which intermodulation products are closest to the original signal frequencies?
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What is the frequency deviation for a 12.21 MHz reactance modulated oscillator in a 5 kHz deviation, 146.52 MHz FM phone transmitter?