What is the Q of a parallel RLC circuit, if it is resonant at 3.625 MHz, L is 42 microhenrys and R is 220 ohms?

The quality factor (Q) of a parallel RLC circuit is determined by the ratio of its parallel resistance to its reactive component at resonance, given by the formula Q = R / X_L. Begin by finding the inductive reactance (X_L = 2πfL). Using the provided values, X_L = 2 × π × 3.625 × 10^6 Hz × 42 × 10^-6 H, which gives about 956.6 ohms. Finally, compute the Q factor by dividing the resistance by the reactance: Q = 220 ohms / 956.6 ohms, which yields approximately 0.23.