What is the Q of a parallel RLC circuit, if it is resonant at 3.625 MHz, L is 43 microhenrys and R is 1.8 kilohms?

To calculate the Q of a parallel RLC circuit, apply the relationship Q = R / X_L. Unlike a series circuit, a higher parallel resistance equates to a higher Q factor. First, calculate the inductive reactance with X_L = 2πfL. Substituting the given values gives X_L = 2 × π × 3.625 × 10^6 Hz × 43 × 10^-6 H, resulting in approximately 979.4 ohms. Then, divide the resistance (1.8 kilohms or 1800 ohms) by the reactance. Q = 1800 / 979.4, which gives 1.837, rounding to 1.84.