If a receiver tuned to 146.70 MHz receives an intermodulation product signal whenever a nearby transmitter transmits on 146.52, what are the two most likely frequencies for the other interfering signal?

Third-order intermodulation products occur when two signals mix in a non-linear circuit, creating unwanted signals at frequencies calculated by the formulas $2f_1 - f_2$ and $2f_2 - f_1$. To find the unknown frequency ($f_2$), we can substitute the known receiver frequency ($f_{IM} = 146.70$ MHz) and known transmitter frequency ($f_1 = 146.52$ MHz) into these equations. First, solve $2(146.52) - f_2 = 146.70$. This gives $293.04 - f_2 = 146.70$, which yields $f_2 = 146.34$ MHz. This provides our first possible interfering frequency. Next, solve $2f_2 - 146.52 = 146.70$. Adding $146.52$ to both sides gives $2f_2 = 293.22$, which means $f_2 = 146.61$ MHz. Therefore, 146.34 MHz and 146.61 MHz are the two most likely frequencies for the other interfering signal.