GeneralG6B10
How does a ferrite bead or core reduce common-mode RF current on the shield of a coaxial cable?
A
Answer
Circuit components
Type
A
By creating an impedance in the current’s path
B
It converts common-mode current to differential mode current
C
By creating an out-of-phase current to cancel the common-mode current
D
Ferrites expel magnetic fields
Answer Notes
A ferrite bead or core placed around a coaxial cable acts as an RF choke. The magnetic properties of the ferrite material add inductance to the outside of the coax shield, which creates a high resistance (specifically, an impedance) to radio frequency currents trying to travel along it.
This added impedance effectively chokes off unwanted "common-mode" currents—currents that flow on the outside of the shield and cause the cable itself to radiate or pick up RF interference.
Ferrites do not create out-of-phase canceling currents, nor do they magically convert common-mode currents into desired differential-mode currents. They simply act as a roadblock (impedance) to stop the unwanted RF current from flowing.
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