AdvancedA-003-006-002

A moving-coil milliammeter having a full-scale deflection of 1 mA and an internal resistance of 0.5 ohms is to be converted to a voltmeter of 20 volts full-scale deflection. It would be necessary to insert a:

D
Answer
Transmitters and receivers
Type
A
shunt resistance of 19 999.5 ohms
B
series resistance of 1 999.5 ohms
C
shunt resistance of 19.5 ohms
D
series resistance of 19 999.5 ohms

Answer Notes

To convert an ammeter (which measures current) into a voltmeter (which measures voltage), a resistor must be added in series. This is known as a multiplier resistor. Shunt resistors are used in parallel to increase current-measuring capacity, so options suggesting a shunt can be immediately eliminated. Using Ohm's Law (R = E / I), the total resistance required for the circuit to read 20 volts at a full-scale current of 1 mA (0.001 amps) is 20 / 0.001 = 20,000 ohms. Since the meter movement itself already has an internal resistance of 0.5 ohms, you must subtract this from the total necessary resistance to find the value of the added resistor. The required series resistor is 20,000 - 0.5 = 19,999.5 ohms.
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A meter has a full-scale deflection of 40 microamperes and an internal resistance of 96 ohms. You want it to read 0 to 1 mA. The value of the shunt to be used is:
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A voltmeter having a range of 150 volts and an internal resistance of 150 000 ohms is to be extended to read 750 volts. The required multiplier resistor would have a value of: