AdvancedA-003-002-007
What is the output PEP from a transmitter if an oscilloscope measures 500 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?
B
Answer
Transmitters and receivers
Type
A
500 watts
B
625 watts
C
2500 watts
D
1250 watts
Answer Notes
Calculating Peak Envelope Power (PEP) from a peak-to-peak oscilloscope reading requires converting that reading to an RMS voltage before determining power. A fast and reliable shortcut formula for a 50-ohm load is P = (Vp-p)² / (8 * R).
Using this shortcut with the given 500 volts peak-to-peak: (500 * 500) / (8 * 50). This simplifies to 250,000 / 400, which equals 625 watts.
If you prefer the step-by-step method, half of 500V is 250V (peak). Multiplying by 0.707 gives an RMS voltage of 176.75V. Squaring 176.75V and dividing by 50 ohms yields 625 watts. Options like 1250 watts are incorrect because they result from using the peak voltage rather than the RMS voltage in the power formula.
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What is the output PEP from a transmitter if an oscilloscope measures 200 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?
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What is the output PEP of an unmodulated carrier transmitter if a wattmeter connected to the transmitter output indicates an average reading of 1060 watts?