What is the output PEP from a transmitter, if an oscilloscope measures 800 volts peak-to-peak across a 50 ohm dummy load connected to the transmitter output?

To find the Peak Envelope Power (PEP) from a peak-to-peak voltage measurement, the easiest formula to use is P = (Vp-p)^2 / (8 * R). In this question, Vp-p is 800 volts and R is 50 ohms. Plugging the numbers into the formula: square the 800 volts to get 640,000. Next, multiply the 50 ohm load by 8 to get 400. Finally, divide 640,000 by 400, which yields 1600 watts. Alternatively, you can solve this by converting to RMS voltage first. The peak voltage is half of 800V (400V), and the RMS voltage is 400V * 0.707 = 282.8V. Squaring the RMS voltage and dividing by 50 ohms also results in 1600 watts.