AdvancedA-003-002-006
What is the output PEP from a transmitter if an oscilloscope measures 200 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?
A
Answer
Transmitters and receivers
Type
A
100 watts
B
200 watts
C
1000 watts
D
400 watts
Answer Notes
To find Peak Envelope Power (PEP) from a peak-to-peak (P-P) voltage measurement on an oscilloscope, you must first convert the voltage to its Root Mean Square (RMS) value. Start by dividing the P-P voltage by 2 to get the peak voltage (200V / 2 = 100V). Next, multiply the peak voltage by 0.707 to find the RMS voltage (100V * 0.707 = 70.7V).
Now you can use the standard power formula, P = E² / R, where E is the RMS voltage and R is the resistance. Squaring 70.7V gives approximately 5000. Dividing this by the 50-ohm load resistance gives exactly 100 watts.
Alternatively, you can use the shortcut formula: P = (Vp-p)² / (8 * R). Plugging in the numbers: (200 * 200) / (8 * 50) = 40,000 / 400 = 100 watts. Distractor answers usually result from forgetting to convert P-P voltage to RMS before calculating power.
Previous · A-003-002-005
How is the output Peak-Envelope Power of a transmitter calculated if an oscilloscope is used to measure the Peak-Envelope Voltage across a dummy resistive load (where PEP = Peak-Envelope Power, PEV = Peak-Envelope Voltage, Vp = peak-voltage, RL = load resistance)?
Next · A-003-002-007
What is the output PEP from a transmitter if an oscilloscope measures 500 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?