AdvancedA-003-002-005
How is the output Peak-Envelope Power of a transmitter calculated if an oscilloscope is used to measure the Peak-Envelope Voltage across a dummy resistive load (where PEP = Peak-Envelope Power, PEV = Peak-Envelope Voltage, Vp = peak-voltage, RL = load resistance)?
A
Answer
Transmitters and receivers
Type
A
PEP = [(0.707 PEV)(0.707 PEV)] / RL
B
PEP = [(Vp)(Vp)] / (RL)
C
PEP = (Vp)(Vp)(RL)
D
PEP = [(1.414 PEV)(1.414 PEV)] / RL
Answer Notes
An oscilloscope displays the actual peak-to-peak or peak voltage of an RF signal. To find Peak-Envelope Power (PEP), you must identify the highest amplitude cycle (the Peak-Envelope Voltage, or PEV) and convert it to an equivalent power value.
Power is calculated using the formula P = V^2 / R, but the voltage must be in RMS (Root Mean Square). For a pure sine wave, the RMS voltage is the peak voltage multiplied by 0.707.
By multiplying PEV by 0.707, you obtain the RMS voltage of that peak cycle. Squaring this value—represented as (0.707 PEV) multiplied by (0.707 PEV)—and dividing by the load resistance (RL) yields the PEP. The option using 1.414 is incorrect because that multiplier is used to convert RMS up to peak, not peak down to RMS.
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The formula to be used to calculate the power output of a transmitter into a resistor load using a voltmeter is:
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What is the output PEP from a transmitter if an oscilloscope measures 200 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?